"I was finishing a backgammon game and had two pieces left, one on 4, and the other on two. I rolled a six, 3, and I believed the backgammon game was over, but my opponent said that I had to move my 4 piece to the one slot, then consider the 2 off with the 6 roll.  She stated I had to do this simply because I had the possibility to move my piece, it is a backgammon rule! I've received $. riding on this, is it correct? What is the right backgammon rule? Please react!"

We have received many messages as the above 1 and made the decision to provide a useful formula for beginners. The formula is really straightforward:

"If the quantity of the dice that you have rolled is equal or larger than the quantity of the row* that your checker** is situated you bear off. If the dice amount is smaller sized than the row quantity you need to play that quantity by moving your checker in direction of rows with smaller number."

Row*: the area, the slot, the field. that you perform or spot your checkers. 24 rows exist on the backgammon board.


Checker**: the stone, the piece. that you play on the board. Egp88 slot login Each and every player has 15 checkers.

The formula might seem tough but do not worry, it really is not, let me clarify! To start to bear off you must enter all your checkers into your home region and in your house location you have 6 rows. Let's place a quantity to every of these 6 rows. The first a single is "r1" which is also the row that your opponent's two checkers are positioned on the beginning of the game.

Then you have "r2", "r3", "r4", "r5" lined side by side and the final 1 is "r6" in which you place five checkers on the starting. Now you know that the row quantity is a quantity in between one and 6. Same of the dice number!

Now suppose that you have one checker in row 5 and one checker in row 2 (better is to use your actual backgammon board and simulate individuals possibilities), and you have rolled a "six + three", six is larger than five and three is greater than two, and you bear off your two checkers!

Suppose you have 2 checkers in "r4" and a single checker in "r1", you have rolled a "four + 3", you bear off 1 checker from "r4" with your dice quantity four, and for dice number 3 you must move one checker from "r4" to "r1".

You have three checkers in "r6" and two checkers in "r3", four checkers in "r2" and three checkers in "r1". You have rolled a "five + 4". Regrettably you will move two checkers from "r6" to "r2" and "r1", and you can not bear any checker off.

You have three checkers in "r6", three in "r5", two in "r4", 4 in "r2" and 3 in "r1", and you have rolled a "double3", because your "r3" is empty you must move two checkers from "r6" to "r3" and bear 2 checkers off from "r3".

You have 3 checkers in "r3", 4 checkers in "r2" and five checkers in "r1", you have rolled a "five + four". You will bear 2 checkers off from "r3".

You have two checkers in "r6", 4 checkers in "r5", one checker in "r4", three checkers in "r3", 3 checkers in "r2" and 2 checkers in "r1". You have rolled a "double4". You will bear one checker off from "r4", move 2 checkers from "r6" to "r2" and one checker from "r5" to "r1". Only a single checker has been born off.

Maybe the worst position is when you have only two checkers remaining in "r2" and you roll a single "one", for example a "three + one". Whilst 3 is bigger than "r2", one is smaller sized, and you will bear a single checker off but move the last a single to "r1" and wait for the next hand. Same for "two + 1" or "4 + one"